Structured arrays type definition

Numba Community Support
1

Is there a reason for structured array type having to be defined outside Numba function? This snippet:

import numpy as np, numba as nb

Point = np.dtype([('x', 'f4'), ('y', 'f4')])

@nb.njit
def f():
  a = np.zeros((2,), dtype=Point)
  # a = np.zeros((2,), dtype=np.dtype([('x', 'f4'), ('y', 'f4')]))
  a['x'][0] = 42
  return a

compiles, but the commented line doesn’t.